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A charge q is placed at the centre of th...

A charge q is placed at the centre of the line joining two equal charges Q. and Q.. The system of the three charges will be in equilibrium, if q is equal to

A

`-(Q.)/(2)`

B

`-(Q.)/(4)`

C

`+(Q.)/(4)`

D

`(Q.)/(2)`

Text Solution

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According to the question,

For the system to be in equilibrium,
`(1)/(4piepsilon_(0))(Q.q)/(x^(2))=(-1)/(4piepsilon_(0))(Q.^(2)q)/((2x)^(2))`
`q=(-Q.)/(4)`
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