H2S is passed through an acidified solut...

`H_2S` is passed through an acidified solution of copper sulphate and a black precipitate is fromen. This is due to :

oxidation of `Cu^(2+)`

reduction of `Cu^(2+)`

oxidation of `Cu^(2+)` and then reduction

neither oxidation nor reduction of `Cu^(2+)`

Verified by Experts

The correct Answer is:

In this reaction, there is niether oxidation nor reduction of `Cu^(2+)`

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