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Why Sm^(2+), Eu^(2+) and Yb^(2+) ions i...

Why `Sm^(2+), Eu^(2+)` and `Yb^(2+)` ions in solutions are good reducing agents, but an aqueous solution of `Ce^(4+)` is a good oxidising agent.

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(a) Separation of lanthanide elements is difficult. Explain. (b) Sm^(2+), Eu^(2+) and Yb^(2+) ions in solutions are good reducing agents but an aqueous solution of Ce^(4+) is a good oxidising agent. Why?

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