Draw the perpendicular bisector of `bar XY`` whose length is 10.3 cm
Take any point P on the bisector drawn.Examine whether PX=PY.

bar(XY) is perpendicular bisector of bar(PQ) then angle between bar(XY) and bar(PQ) is

Two point charges q and -q is placed at a distance 2a apart.Calculate the electric field at a point P situated at a distance r along the perpendicular bisector of the line joining the charges. What is the electric field when r gtgt a ? Also, give the direction of electric field W.r.t. electric dipole moment? .

Two particles of equal masses m and m are connected by a light string of length 2l. A constant force F is applied continuously at the mid-point of the string, always along the perpendicular bisector of the straight line joining the two particles. Show that when the distance between the two particles is x, the acceleration of the particle is a = F/m = (x)/((1^2 - x^2) ^(1//2)

A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p, If the distance of Q from the dipole is r (much larger than the size of the dipole), then electric field at Q is proportional to

Find the equation of the perpendicular bisector of the st. line segment whose end points are (0, 5) and (- 4,1).

If perpendiculars from any point within an angle on its forms arms are congruent prove that it lies on the bisector of that angle.