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Charges +q and -q are placed at points A...

Charges `+q` and `-q` are placed at points `A` and `B` respectively which are a distance `2L` apart, `C` is the midpoint between `A` and `B`. The work done in moving a charge `+Q` along the semicircle `CRD` is

A

`(qQ)/(2pi epsilon_(0)L)` and infinity

B

`(qQ)/(6pi epsilon_(0)L)` and zero

C

zero, zero

D

`(-qQ)/(6pi epsilon_(0)L)` and zero

Text Solution

Verified by Experts

The correct Answer is:
D
`W_(CRD)=Q(V_(D)-V_(C ))`
`=Q[V_(D)-o] `(`:.` potential at centre of dipole is zero)
`=[(kq)/(3L)-(kq)/(L)]Q`
`W_(CRD)= -(kqQ)/(L) xx (2)/(3) = -(qQ)/(6pi epsilon_(0)L)`
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