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The limiting molar conductivities Lambda...

The limiting molar conductivities `Lambda^@` for `NaCL, KBr` and `KCI` are ` 126, 152` and `150 S cm^2 ,ol^(-1)` respectively . The `Lambda^@` fro `NaBr S cm^2 "mol"^(-1)` is :

A

128 `"S cm"^(2)"mol"^(-1)`

B

302 `"S cm"^(2)"mol"^(-1)`

C

278 `"S cm"^(2)"mol"^(-1)`

D

176 `"S cm"^(2)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Lambda_(NaBr)^(@)=Lambda_(NaCl)^(@)+Lambda_(KBr)^(@)-Lambda_(KCl)^(@)=126+152-150=128"S cm"^(2)"mol"^(-1)`
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