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What is the ratio of lamda(max)andlamda(...

What is the ratio of `lamda_(max)andlamda_(min)` for Balmer series of hydrogen spectrum ?

A

`4/3`

B

`3/4`

C

`9/5`

D

`5/9`

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Calculate the wavelength of the first and the last line in the Balmer series of the hydrogen spectrum.

For one-electron species, the wave number of radiation emitted during the transition of electron from a higher energy state (n_(2)) to a lower energy state (n_(1)) is given by: bar v =(1)/(lamda)=R_(H) xx Z^() ((1)/(n_(1)^(2)) (1)/(n_(2)^(2))) where R_(H)=(2 pi m_(s) k^(2) c^(4))/(h^(3) c) is Rydberg constant for hydrogen atom. Now, considering nuclear motion, the accurate measurement would be obtained by replacing mass of electron (m_(e)) by the reduced mass (mu) in the above expression, defined as mu =(m_(n)xx m_(e))/(m_(n) +m_(e)) where m_(n) = mass of nucleus. For Lyman series, n_(t) =1 (fixed for all the lines) while n_(2) = 2, 3, 4 .... For Balmer series: n_(1) = 2 (fixed for all the lines) while n_(2) = 3,4,5 .... The ratio of the wave numbers for the highest energy transition of electron in Lyman and Balmer series of hydrogen atom is

Bohr was the first to explain the structure of hydrogen atom and spectrum. Calculate the wavelength of the first line in the Lyman series of the hydrogen spectrum. ( R= 109677 cm^(-1))

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