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One mole of magnesium in the vapour stat...

One mole of magnesium in the vapour state absorbed 1200 kJ 'm o l^(-1)' of energy. If the first and second ionization energies of 'Mg' are 750 and '1450 kJ mol^(-1)' respectively, the final composition of the mixture is

A

`69%Mg^(+)`

B

`69%Mg^(2+)`

C

`59%Mg^(+)`

D

`59%Mg^(2+)`

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BRILLIANT PUBLICATION-CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES-LEVEL - II
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