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(3N(0))/2 atoms of X((g)) are converted ...

`(3N_(0))/2` atoms of `X_((g))` are converted into `X_((g))^(+)` by energy `E_(1),(2N_(0))/3` atoms of `X_((g))` are converted into `X_((g))^(-)` by energy `E_(2)`. Hence ionisation energy and electron gain enthalpy of `X_((g))` are (`N_(0)` = Avogadro Number)

A

`(2E_(1))/(3N_(0)),(2E_(2))/(3N_(0))`

B

`(2E_(1))/(3N_(0)),(3E_(2))/(2N_(0))`

C

`(3E_(1))/(2N_(0)),(3E_(2))/(2N_(0))`

D

`(3E_(1))/(2N_(0)),(2E_(2))/(3N_(0))`

Text Solution

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