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H (2 ) + 1/2 O (2) to H (2) O, Delta H =...

`H _(2 ) + 1/2 O _(2) to H _(2) O, Delta H =- 68` kcal
`K + H _(2) O + aq to KOH _((aq)) + (1)/(2) H _(2) , Delta H =- 48` kcal
`KOH + aq to KOH _((aq)) , Delta H =- 14 `kcal
From the above data `Delta H _((f))`of KOH in kcal is

A

`-130`

B

`130`

C

`+102`

D

`-102`

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