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2 g of CaCO(3) on strong heating gave 1....

2 g of `CaCO_(3)` on strong heating gave `1.12 g` of CaO and 448 ml of `CO_2`. Show that the results illustrate the law of conservation of mass.

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Verified by Experts

`22400 ml" of "CO_2` weights 44g.
Therefore, mass of `448 ml CO_(2)=(448 mlxx44 g)/(22400 ml)=0.88 g`
Weights of `CaO+CaO_(2)` = Weight of `CaCO_(3) implies 1.12+0.88=2.00 g`
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