Calculate the mass of `CaO` formed from `25g` of `CaCO_(3)` on strong heating (mol.mass of `CaCO_(3)=100" and "CaO=56`).

Explanation

`CaCO_(3(s)) overset(triangle)(to) CaO_((s))+CO_(2)(g)`
Number of moles of `CaCO_(3) = (" Mss of " CaCO_(3))/(" Mol. Mass of "CaCO_(3))= (25)/(100)=0.25`
Mole ratio of `CaCO_(3)" and "CaO = 1:1` (from equation)
Number of moles of `CaO=0.25(1/1)=0.25`
Mass of `CaO` formed `=0.25xx56=14 g`.