Construct an ionic equation for the neutralisation of `HNO_3` and KOH.

Explanation

`H_((aq))^(+)+NO_(3(aq))^(-)+K_((aq))^(+)+OH_((aq))^(-) to K_((aq))^(+)+NO_(3(aq))^(-)+H_(2)O_(l)`
Crossing out spectator ions : `H_((aq))^(+)+OH_((aq))^(-) to H_(2)O_(l)`
(This ionic equation is true for all neutralisation reactions irrespective of the acid and base used.)