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250mL of 0.2M H(2)SO(4) is mixed with 10...

`250mL` of `0.2M H_(2)SO_(4)` is mixed with 100mL of `0.5M H_(2)SO_(4)`. What is the molarity of the resulting solution?

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Final molarity `=(" Total moles of "H_(2)SO_(4))/(" Total volume ")= (M_(1)V_(1)+M_(2)V_(2))/(V_(1)+V_(2))= ((250xx0.2)+(100xx0.35))/(250+100)=(50)/(350)=0.14`
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