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What is the final molarity of a solution...

What is the final molarity of a solution of `9.8g H_(2)SO_(4)` in 250mL water when mixed with 250mL of `0.1M H_(2)SO_(4)`?

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Molarity of `H_(2)SO_(4)` solution containing `9.8 g" in "250 mL" water "=(9.8xx1000)/(98xx250)=0.4`
When 250 ml of `0.4 M` solution is mixed with 250 mL `0.1 M` solution
Find molarity `=((250xx0.4)div(250xx0.1))/(250+250)=0.25`
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