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Calculate the pH value of the following ...

Calculate the pH value of the following solution:
`0.0001M""NaOH`.

Text Solution

Verified by Experts

NaOH is fully ionised, therefore, `[NaOH]= [OH^-]=0.0001M = 10^(-4)M`
`[H^+]= (10^(-14))/(10^(-4)) = 10^(-10) implies pH= -log(10^(-10))=10`.
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