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0.2 g of a substance displaced 65.2 mL o...

`0.2 g` of a substance displaced `65.2 mL` of air at 300 K and 749 mm pressure. Calculate the molecular mass of the substance. (Aqueous Tension at 300 K is `26.7mm`)

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Given : Mass of substance `=0.2 g` , Volume of air `(V) = 65.2 mL` , Temperature `=300K`
Pressure `(P) =749-26.7=722.3`
Molar mass, `M=(w xx RT xx760xx1000)/((P-p)xxV) =(760xx1000xx0.2xx0.0821xx300)/(722.3xx65.2) =79.5 g mol^(-1)`.
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