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1.9g of the chloroplatinate of a diacid ...

`1.9g` of the chloroplatinate of a diacid base when ignited left `0.75g` of Pt. Calculate the molecular mass of the base. (Atomic mass of Pt is 195)

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Mass of platinic chloride `(W)-1.9 g ""12`
Mass of Pt obtained `(x) =0.75g`
Acidity of base `(n)=2`
Molar mass of base `=(n)/(2)((195xxW)/(x)-410)= (2)/(2) ((195xx1.9)/(0.75)-410)" "=84g"mol^(-1)`.
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