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The mass of NaBrO3 required to prepare 1...

The mass of `NaBrO_3` required to prepare 150 mL of `0.75 N` of a solution based on the reaction `BrO_(3)^(-)+ 6H^(+) + 6e^(-) to Br^(-)+3H_(2)O` is

A

`1.42 g`

B

`2.83 g`

C

`3.85 g`

D

`4.25 g`

Text Solution

Verified by Experts

The correct Answer is:
B
Amount of `NaBrO_(3)` in the solution `=(0.75 eq dm^(-3)) (0.150dm^(-3))=0.1125 eq`
Mass of `NaBrO_(3)` required `=(0.1125 eq) (0.151"/"6) g""eq^(-1)=2.83 g`.
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