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What is the empirical formula of vanadiu...

What is the empirical formula of vanadium oxide, if `2.74 g` of the metal oxide contains `1.53 g` of metal ? (Atomic mass of vanadium=52 u)

A

`V_(2)O_(3)`

B

`VO`

C

`V_(2)O_(5)`

D

`V_(2)O_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Metal oxide `=2.74 g, %" of " V =(1.53)/(2.74)xx100=55.83`
Thus, % of `O =100-55=44.17`
No. of moles of V `=(55.83)/(52)=1.1" "` No. of moles of `O =(44.17)/(16)=2.76`
simplest ratio of V and `O =1:2.5" or "2:5` Hence, the emprical formula `=V_(2)O_(5)`
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