Calculate the number of atoms of oxygen present in `88 g ""CO_2`. What would be the mass of CO having the same number of oxygen atoms?

Options

A. `98 g CO`
B. `120 g CO`
C. `112 g CO`
D. `132 g CO`

Answer

C

Explanation

`:.` Molar mass of `CO_(2)=44` and it has 32 g `O_2` and one molecule of `O_2` has 2 atoms.
`:." " 44 g CO_(2)=2 N` atoms of O
`:." "88 g CO_(2)= (2xx6.02xx10^(23)xx88)/(44)` atoms of `O=24.092xx10^(23)` atoms of Oxygen
Also, molar mass of `CO=28` and it has 16g O and atom of O in one molecule of CO.
N atoms of O are present in `=28 g CO`
`:." "24.092xx10^(23)` atoms of O are present in `(28xx24.092xx10^(23))/(6.02xx10^(23)) =112 g CO`.