The percentage composition (by weight) of a solution is 45%X, 15%Y,and 40% Z. Calculate the mole fraction of Z component of the solution.(Molecular mass of X = 18,Y=60 and Z = 60)

Options

A. `0.87`
B. `0.197`
C. `0.259`
D. `0.216`

Answer

B

Explanation

No. of moles of `X=45%, n_(1)=(45)/(18)=2.5`
`Y=15%, n_(2)=(15)/(60)=0.25," "Z=40%, n_(3)= (40)/(60)=0.666`
`chi_(1)=(n_1)/(n_(1)+n_(2)+n_(3))=(2.5)/(2.5+0.25 +0.666)=(2.5)/(3.416)=0.73`
`chi_(2) =(n_2)/(n_(1)+n_(2)+n_(3))=(0.25)/(3.416) =0.073`
`chi_(3)=[1-(chi_(1)+chi_(2))]=(1-0.73-0.073)=0.197`.