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One litre of N"/"2 HCI solution was heat...

One litre of `N"/"2 HCI` solution was heated in a beaker. When the volume was reduced to `600mL, 9.125 g` of HCI was lost out, the new normality of solution is

A

`approx 0.04`

B

`approx 0.8`

C

`approx 0.4`

D

`approx 0.2`

Text Solution

Verified by Experts

The correct Answer is:
C
`HCl overset(triangle)(to) HCl, 0.5 N xx 1 L =0.5 Eq=0.5xx36.5 g =18.25 g`
Mass of HCl left after heating `=18.25-9.125=9.125 g`
`N_("new")" of "HCl= (9.125xx1000)/(36.5xx600) =0.416 N`.
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