10mL of `0.2 N` HCI and 30mL of `0.1 N` HCI together exactly neutralise 40 mL of solution of NaOH, which is also exactly neutrlised by a solution in water of `0.61 g` of an organic acid. What is the equivalent acid. What is the equivalent weight of the organic acid?

Options

A. `61`
B. `91.5`
C. `122`
D. `183`

Answer

B

Explanation

10mL of `0.2N""HCI+30mL` of `0.1N""HCI = 40 mL` of `NaOH(=0.61 g" organic acid ")`
mEq of HCI = mEq of NaOH =mEq of organic acid
`10xx0.2+30xx0.1=(0.61)/( E)xx1000 implies5= (0.61xx100)/(E )implies E=(610)/(5)=122`