Resultant molarity of `H^+` ion in a mixture of 100 mL of `0.1 M""H_(2)SO_(4)` and200 mL of `0.1 H_(3)PO_(3)` is:

Options

A. `0.1`
B. `0.2 M`
C. `0.267 M`
D. `0.133 M`

Answer

D

Explanation

`H^(+)(" in "H_(2)SO_(4)" -a dibasic acid ")=0.2M`
`H^(+) (" in "H_(3)PO_(3)" -a dibasic acid ")=0.2 M`
Total `[H^+]=(M_(1)V_(1)+M_(2)V_(2))/(V_(1)+V_(2))=(100xx0.2+200xx0.2)/(300)=0.2 M`.