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The percentage ionic character of a bond...

The percentage ionic character of a bond A-B is 86.41% and the bond length is 162.3 pm. What is the dipole moment of the molecule?

Text Solution

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If the molecule were 100% ionic, then `mu_("ionic")=Q xx r`
`mu_("ionic") = 1.602xx10^(-19) (C)xx162.3xx10^(-12)(m) = 2.600xx10^(-29)` Cm
`mu_("obs")=("%ionic character" xx mu_("ionic"))/(100)=(86.41xx 2.60xx10^(-29))/(100) = 2.25xx10^(-29)` Cm
Dipole moment of molecule `AB=(2.25xx10^(-29))/(3.335xx10^(-30)) =6.75D` (`:. 1D=3.335xx10^(-30)` Cm)
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