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The electronegativities of H and F are 2...

The electronegativities of H and F are 2.1 and 4.0 respectively. What is the percentage ionic character of HF bond on the basis of Hanny Smith equation?

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Electronegativities of H, `X_H = 2.1` and F, `X_F=4.0`
By Hanny and Smith equation, % ionic character, `P=16 [X_B -X_A]+3.5[X_B -X_A]^2`
Percentage ionic character, `P = 16 (4-2.1)+3.5(4-2.1)^2 = 16xx1.9+3.5(1.9)^2 = 43.0`
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