Among the following species, identify the isostructural pairs : `NF_3, NO_3^(ѳ), BF_3, H_3 overset(o+)O, N_3H`. : `[NF_3, NO_3^(ѳ)]` and `[BF_3, H_3 overset(o+)O]`; `[NF_3, N_3H]` and `[NO_3^(ѳ), BF_3]`; `[NF_3, H_3 overset(o+)O]` and `[NO_3^(ѳ), BF_3]`;

Options

A. `[NF_3, NO_3^(ѳ)]` and `[BF_3, H_3 overset(o+)O]`
B. `[NF_3, N_3H]` and `[NO_3^(ѳ), BF_3]`
C. `[NF_3, H_3 overset(o+)O]` and `[NO_3^(ѳ), BF_3]`
D. `[NF_3, H_3 overset(o+)O]` and `[N_3H, BF_3]`

Answer

C

Explanation

`ddotN F_3 implies 1/2(5+3)= 4= sp^3" "NO_3^(ѳ) implies 1/2(5+0+1)=3=sp^2`
`BF_3 implies 1/2(3+3) = 3=sp^2" "H_3O^(o+) implies 1/2(6+3-1)= 4=sp^3`
`HN_3` (Hydrazoic acid) is sp hybridised and is linear:
`NF_3` and `H_3O^(o+)` are pyramidal. `NO_3^(ѳ)` and `BF_3` are trigonal planar.