A gas cylinder can withstand a pressure of `14.5 atm`. A pressure gauge connected to it reads `11.5atm` at `30^(@)C`. What is the maximum temperature that the cylinder can withstand without exploding?

Explanation

Given : `P_(1)= 11.5 atm, T_(1)= (273+30)= 303^(@)C, P_(2)= 14.5 atm, T_(2)= ?`
By Gay Lussac.s law : `(P_1)/(T_1)= (P_2)/(T_2) implies T_(2)= (P_(2)xx T_(1))/(P_1)= (14.5 atm xx 303K)/(11.5atm)= 382K (109^(@)C)`.