`5.0g` of oxygen is introduced into an evacuated vessel of `10 dm^3` capacity maintained at `25^(@)C`. Calculate the pressure of the gas in the container assuming that the gas behaves ideally.

Explanation

Given : `V= 10 dm^(3), T= 25+273= 298K, R= 0.0821 dm^(3) atm K^(-1) mol^(-1), n= w"/"M= 5g"/"32g"" mol^(-1) = 0.156 mol^(-1)`
Pressure of gas, `P= (nRT)/(V)= (0.156 mol xx 0.0821 dm^(3) atm K^(-1) mol^(-1) xx 298 K)/(10 dm^(3))= 0.382 atm`