Calculate the average translation kinetic energy of an ideal gas per molecule `(epsilon)` and per mole (E ) at `25^(@)C`. (Boltzmann constant, `k= 1.38 xx 10^(-23)JK^(-1)`).

Explanation

`epsilon= (3)/(2)kT= 3"/"2(1.38xx 10^(-23)jK^(-1))(298K)= 6.17 xx 10^(-21)J" molecule "^(-1)`
`E= (3)/(2)RT= 3"/"2(8.314JK^(-1)mol^(-1))(298K)= 3.716xx 10^(3) J mol^(-1)`.