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For oxygen gas at 27^(@)C, calculate the...

For oxygen gas at `27^(@)C`, calculate the mean free path at `10^(-5)mm Hg` pressure. The collision diameter of oxygen molecule is 361 picometre.

Text Solution

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To calculate mean free path at `10^(5)mm Hg`
Pressure, `P= 10^(5) mm Hg = ((10^(-3)mm Hg)(1.01325 xx 10^(5)Nm^(-2)atm^(-1)))/(760 mm Hg atm^(-1))= 0.1333 Nm^(-2)`
Mean free path, `lambda=(1.38xx 10^(-23)JK^(-1)(300K))/((1.4142)(3.1416)(3.61xx 10^(-10)m)^(2)(0.1333Nm^(-2)))= 5.3 xx 10^(-2)m`.
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