The vapour pressure of water at `80^(@)C" is "355 mm Hg`. A one-litre vessel contains `O_(2)" at "80^(@)C`, saturated with water vapour the total pressure being 760 mm Hg. The contents of the vessel were pumped into `0.3L` vessel at the same temperature. What is the partial pressure of `O_(2)`?

Options

A. `1350 mm Hg`
B. `2263.3 mm Hg`
C. `123.5 mm Hg`
D. `455 mm Hg`

Answer

A

Explanation

Given that `P_(H_2O)= 355 mm Hg" at "80^(@)C, P_(O_2)= 405 mm Hg`.
According to Boyle.s law, `p_(1)V_(1)= P_(2)V_(2)`. Substituting values, we get
`p_(1)= (405xx 1)/(0.3)= 1350 mm Hg`.