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Two moles of a gas confined in a 4L flas...

Two moles of a gas confined in a 4L flask exert a pressure of `11.0 atm" of "300 K` temperature. The value of b is `0.05L mol`, the value of a is

A

`6.00 L atm mol^(-2)`

B

`6.52 L atm mol^(-2)`

C

`6.46 L atm mol^(-2)`

D

`6.46 L atm mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Using van der Waals equation, we have `(p+(an^2)/(V^2))(V-nb)= nRT, (an^2)/(V^2)= (nRT)/(V- nb)-p`
`(a xx 4)/(6)= (2xx 0.0821 xx 300)/(4-2 xx 0.05)-11 implies (a xx 4)/(16)= 1.631" or " a= (1.631 xx 16)/(4)= 6.522 L^(2) atm mol^(-2)`.
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