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1 mol" of "N(2) gas at 0.8 atm takes 38s...

`1 mol" of "N_(2)` gas at `0.8 atm` takes 38s to diffuse through a pinhole, whereas 1 mol of an unknown gas at `1.6 atm` takes 57s to diffuse through the same pinhole. The molecular weight of unknown gas is

A

`126`

B

`64`

C

`80`

D

`252`

Text Solution

Verified by Experts

The correct Answer is:
D
`(n_1)/(t_1)xx(t_2)/(n_2)= (p_1)/(p_2)xx sqrt((M_2)/(M_1)) implies(1)/(38)xx (57)/(1)= (0.8)/(1.6)sqrt((M_2)/(28)) implies M_(2)= 252`.
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