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What will be the molecular diameter of h...

What will be the molecular diameter of helium if van der Waals constant, `b=24 mL mol^(-1)`?

A

`2.67 A^0`

B

`2.67 nm`

C

`5.42 A^0`

D

`542 A^0`

Text Solution

Verified by Experts

The correct Answer is:
A
`b= 4V_(m) implies 24 = 4 xx N_(A)xx (4)/(3)pr ""r^(3)`
`r= [(3xx 24)/(16 xx (22"/"7)xx6.02 xx 10^(23))]^(1/3)`
Therefore, `d= 2r= 2xx 1.335 xx 10^(-8) cm = 2.67 dotA`.
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