Many laboratory gases are sold in steel cylinders with a volume of `43.8L`. What mass (in grams) of argon is inside a cylinder whose pressure is `17,180 kPa` at `20^(@)C`?

Options

A. `13.3kg`
B. `12.35kg`
C. `11.3kg`
D. `10.3kg`

Answer

B

Explanation

Given : `V= 43.8L, Ar" mass "= ?, p= 17180 kPa= 169.6 atm, T= 293K`
Using `pV= nRT implies n= (pV)/(RT)= (169.6 xxx 43.8)/(0.082 xx 293)= 309.2 mol`
Mass of Argon = moles (n) `xx` Atomic mass of `Ar= 309.2 xx 39.95 = 12, 352g= 1.2352 xx 10^(4)g`.