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At STP, a container has 1 mole of He, 2 ...

At STP, a container has 1 mole of He, 2 mole Ne, 3 mole `O_(2)` and 4 mole `N_(2)`. Without changing total pressure if 2 mole of `O_(2)` is removed, the partial pressure of `O_(2)` will be decreased by:

A

`26%`

B

`40%`

C

`58.33%`

D

`66.66%`

Text Solution

Verified by Experts

The correct Answer is:
C
`P_(O_2)= (3)/(10)xx P_(r )`
After removing 2 mole of `O_(2) implies P._(O_2)= (1)/(8)xx P_(r )`
Decreasing in p.pr. Of `O_(2)= ((3P_r)/(10)-(P_r)/(8))/((3P_T)/(10))xx100= 58.33`.
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