Calculate relative rate of effusion of `SO_(2)" to "CH_(4)`, if the mixture obtained by effusing out a mixture with molar ratio `(n_(SO_2))/(n_(CH_4))=(8)/(1)` for three effusing steps.

Options

A. `2 : 1`
B. `1 : 4`
C. `1 : 2`
D. `3 : 1`

Answer

C

Explanation

`(P_(3(SO_2)))/(P_(3(CH_4)))=(P_(SO_2))/(P_(CH_4))((M_(CH_4))/(M_(SO_2)))^(3/2)`
`(8)/(1) = (P_(SO_2))(P_(CH_4))(1)/(8), (n_1(SO_2))/(n_(1(CH_4)))=1 therefore=(n_1(SO_2))/(n_(1(CH_4)))=sqrt((16)/(64))= (1)/(2)`