Calculate the volume occupied by 16 gram `O_(2)`, at 300 K and `8.31 Mpa` if `(P_(c )V_(c ))/(RT_(c ))= (3)/(8)" and "(P_(r )V_(r ))/(T_(r ))=2.21` (Given : `R= 8.314 J"/"K-mol`)

Options

A. `125.31 mL`
B. `124.31 mL`
C. `248.62 mL`
D. `223.62 mL`

Answer

B

Explanation

`(pV_(m))/(RT)= (3)/(8)xx 2.21, V_(m)= ((3)/(8)xx 2.21)xx (RT)/(P)`
`V_(m)= (3)/(8)xx 2.21 xx (8.314 xx 300)/(8.314)= 248.625 mL`
`V_(O_2)= (16)/(32) = 248.625 = 124.31 mL`.