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Gas molecules each of mass 10^(-26)kg ar...

Gas molecules each of mass `10^(-26)kg` are taken in a container of volume `1 dm^(3)`. The root mean square speed of gas molecules is `1 km sec^(-1)`. What is the temperature of gas molecules?(Given: `N_(A)= 6xx 10^(23), R= 8J"/"mol.K`).

A

`298 K`

B

`25 K`

C

`250 K`

D

`2500 K`

Text Solution

Verified by Experts

The correct Answer is:
C
`1000 = sqrt((3RT)/(M)), 10^(3)= [(3xx 8.314 xx T)/(10^(-26)xx 6 xx 10^(23))]^(1/2)`
`T= (10^(6) xx 10^(-26)xx 6 xx 10^(23))/(3xx 8.314)= 240K`.
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