1.22 g of a gas measured over water at 15°C and a pressure of 775 mm of Hg Occupied 900 ml. Calculate the volume of dry gas at vapour pressure of water at `15^(@)C` is 14 mm of Hg

Options

A. `372.21 mL`
B. `854.24 mL`
C. `869.96 mL`
D. `917.76 mL`

Answer

B

Explanation

Pressure of dry gas = Pressure of moist gas - Vapour pressure of water `=775 - 14 = 761 mm`
From, `{:((p_(1)V_(1))/(T_1)=(p_(2)V_(2))/(T_2)),(" initial NTP"):} implies V_(2)= (p_(1)V_(1)T_(2))/(T_(1)p_(2))= (761xx 900 xx 273)/(288 xx 760)= 854.24 mL`.