Two closed vessels of equal volume containing air at pressure `p_1` and temperature `T_1` are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at `T_1` and that in the other at `T_2`, what will be the pressure in the vessels?

Options

A. `(2p_(1)T_(1))/(T_(1)+T_(2))`
B. `(T_(1))/(2p_(1)T_(2))`
C. `(2p_(1)T_(2))/(T_(1)+T_(2))`
D. `(2p_(1))/(T_(1)+T_(2))`

Answer

C

Explanation

Volume of the system and amount of gas remains constant. Applying Charle.s law,
`(p_1)/(T_1)+(p_1)/(T_1)= (p)/(T_1)+(p)/(T_2) implies (2p_1)/(T_1)= p((T_(1)+T_(2))/(T_(1)T_(2)))" or "p= (2p_(1)T_(1))/(T_(1)+T_(2))`.