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The ratio of average speed of an oxygen ...

The ratio of average speed of an oxygen molecule to the rms speed of a nitrogen molecule at the same temperature is : `((3pi)/(7))^(1/2)`, `((7)/(3pi))^(1/2)`, `((7)/(3pi))^(1/2)`, `((7pi)/(3))^(1/2)`

A

`((3pi)/(7))^(1/2)`

B

`((7)/(3pi))^(1/2)`

C

`((3)/(7pi))^(1/2)`

D

`((7pi)/(3))^(1/2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`u_(av)= sqrt((8RT)/(piM))" So, "u_(av(O_2))= sqrt((8RT)/(pi xx 32))`
`u_(rms)= sqrt((3RT)/(M))" so "u_(rms(N_2))= sqrt((3RT)/(28))`
`(u_(av(O_2)))/(v_(rms(N_2)))sqrt((8xx 28)/(pi xx 32 xx 3))= sqrt((7)/(3pi))= ((7)/(3pi))^(1/2)`.
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