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A 15.0 L cylinder of Ar gas is connected...

A `15.0 L` cylinder of Ar gas is connected to an evacuated `235.0 L` tank. If the final pressure is 750 mm Hg, what have been the original gas pressure in the cylinder? : `76 atm`, `12.56 atm`, `16.45 atm`, `23 atm`

A

`76 atm`

B

`12.56 atm`

C

`16.45 atm`

D

`23 atm`

Text Solution

Verified by Experts

The correct Answer is:
C
From Boyle.s law `p_(1)V_(1)= p_(2)V_(2)`
`p_(1)= (p_(2)V_(2))/(V_1)= (750 xx 250)/(15)[V= 235+15= 250L]= 12500mm Hg= 16.45 atm`.
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