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For the reaction 2NH(3) (g) to N(2) (g)+...

For the reaction `2NH_(3) (g) to N_(2) (g)+ 3H_(2) (g)`. What is the `%` of `NH_(3)` converted if the mixture diffuses twice as fast as that of `S_(2)` under similar conditions?

A

`3.125`

B

`6.25`

C

`12.5`

D

`9.25`

Text Solution

Verified by Experts

The correct Answer is:
B
Moles of `NH_(3)` taken `= 1= 17g" "` degree of dissociation `= alpha`
Moles of mixture formed `= 1+ alpha" "` average molar mass `=(17)/(1+ alpha)= 16 implies alpha= (1)/(16)= 6.25%`.
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