If `chi_(M), chi_(P)" and "chi_(V)` are mole fraction, pressure fraction and volume fraction respectively of a gaseous mixture, then

Options

A. `chi_(M)= (1)/(chi_P)xx(1)/(chi_V)`
B. `(1)/(chi_(M))= chi_P xx (1)/(chi_V)`
C. `chi_(M)= chi_(P) = chi_(V)`
D. `(chi_(P))= (1)/(chi_M)xx(1)/(chi_V)`

Answer

C

Explanation

`" Total "{:("moles "" pressure "" volume "" temperature "),(n_(1)" "P_(1)" "V_(1)" "T),((n_2)/(n_T)" "(P_2)/(P_T)" "(V_2)/(V_T)" "T):}`
`P_(1)= (n_(1)RT)/(V_1), P_(T)= (n_(1)RT)/(V_T)`
`implies (P_1)/(P_T)= (n_1)/(n_T)xx (V_T)/(V_1)" " therefore chi_(M)= chi_(P) xx chi_(V)`.