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The compressibility factor for definite ...

The compressibility factor for definite amount of van der Waal's gas at `0^(@)C` and 100 atm is found to be `0.5`. Assuming the volume of gas molecules negligible, the van der Waal's constant a for a gas is

A

`1.256 atm L^(2) mol^(-2)`

B

`0.256 atm L^(2) mol^(-2)`

C

`2.256 atm L^(2) mol^(-2)`

D

`0.0256 atm L^(2) mol^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_(m)= (zRT)/(P)= 0.11207" "(P+(a)/(V^2))V= RT`
`PV+(a)/(V)= RT implies z= 1-(a)/(RTV_m)`
`a= 1.256 atm L^(2)mol^(-2)`.
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