Dry ice (solid `CO_(2)`) has occasionally been used as an explosive in mining. A hole is drilled, dry ice and a small amount of gun powder are placed in the hole, a fuse is added, and the hole is plugged. When lit, it explodes up with an immense pressure. Assume that `500.0 g` of dry ice is placed in a cavity with a volume of `0.800 L` and the ignited gun powder heats the `CO_(2)` to 700 K. What is the final pressure inside the hole?

Options

A. `416 atm`
B. `816 atm`
C. `616 atm`
D. `1216 atm`

Answer

B

Explanation

We know, that `44g " of "CO_(2)= 1 mol`
Therefore, `500g " of "CO_(2)= (500)/(44)= 11.36 mol`
Also given that `T= 700K, V= 0.8L`. Now, using the ideal gas equation, we get
`p=(nRT)/(V)= (11.36xx 0.0882xx 700)/(0.8)= 816 atm`.