The average speed at temperature `T^(@)C` of `CH_(4)(g)` is `sqrt((28)/(88)) xx 10^(3) ms^(-1)`. What is the value of T?

Options

A. `240.55^(@)C`
B. `-32.45^(@)C`
C. `3000^(@)C`
D. `-24.055^(@)C`

Answer

B

Explanation

`sqrt((8RT)/(pi M))= sqrt((28)/(88))= sqrt((7)/(22)), (8xx 8.314xx T)/(pi xx 16xx 10^(-3))= (7)/(22)xx 10^(6)`
`T= (1000xx 2)/(8.314)= 240.55K, T^(@)C= 240.55-273= -32.45^(@)C`.